Dodgers' Yoshinobu Yamamoto Loses Perfect Game, Then No-Hitter in 7-1 Victory

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With the Dodgers' 7-1 victory over the White Sox, Yoshinobu Yamamoto fell just short of history, losing both a perfect game and no-hitter in the process.

Yamamoto, who came within four outs of a perfect game and three outs of a no-hitter, gave up a leadoff home run in the ninth inning.

'I do feel a little bit regrettable, because I went into the ninth inning and I was not able to achieve a no-hitter,' Yamamoto said through his interpreter. 'I didn't complete the ninth inning, the no-hitter. But how I was pitching, I was pretty satisfied.'

This was the second time Yamamoto has carried a no-hitter into the ninth inning only to give up a home run.

However, it's worth noting that he took it to another level this time, pitching an impressive game.

With a three-run lead going into the game, Yamamoto took care of the rest, striking out seven White Sox batters and holding them to just six hits.

One of the standout performances of the game was Shohei Ohtani, who hit the second pitch he saw from White Sox starter Sean Burke into the right-field seats.

Ohtani walked in each of his next three times up, showing off his impressive skills at the plate.

Max Muncy added a two-run home run, and Yamamoto's performance was enough to secure the win for the Dodgers.

'I mean, it's just baseball,' Dodgers catcher Dalton Rushing said. 'It sucks. Two years in a row, to lose it like that, it's frustrating. And sometimes you kind of feel a little guilty, even.'

Despite the close calls, the Dodgers emerged victorious, and Yamamoto's impressive performance will not be soon forgotten.

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